| | "I was finishing a backgammon game and had two pieces left, 1 on four, and the other on 2. I rolled a six, 3, and I thought the backgammon game was over, but my opponent stated that I had to move my 4 piece to the 1 slot, then take the 2 off with the 6 roll. She mentioned I had to do this simply because I had the opportunity to move my piece, it's a backgammon rule! I have got $. riding on this, is it correct? What is the appropriate backgammon rule? Please respond!"
We have received many messages as the above 1 and decided to provide a beneficial formula for novices. The formula is quite easy:
"If the quantity of the dice that you have rolled is equal or bigger than the amount of the row* that your checker** is positioned you bear off. If the dice number is smaller sized than the row quantity you must perform that quantity by moving your checker in direction of rows with smaller quantity."
http://www.yeezysboost.us.org/how-a-professional-blackjack-player-made-a-living-at-the-casino/ Row*: the space, the slot, the field. that you perform or location your checkers. 24 rows exist on the backgammon board.
Checker**: the stone, the piece. that you play on the board. Each player has 15 checkers.
The formula could look tough but do not worry, it's not, let me clarify! To begin to bear off you must enter all your checkers into your home region and in your house location you have six rows. Let us put a number to every of these six rows. The first 1 is "r1" which is also the row that your opponent's two checkers are positioned on the beginning of the game.
Then you have "r2", "r3", "r4", "r5" lined side by side and the final a single is "r6" in which you place five checkers on the starting. Now you know that the row amount is a quantity between one and 6. Same of the dice number!
Now suppose that you have 1 checker in row 5 and a single checker in row two (much better is to use your genuine backgammon board and simulate individuals choices), and you have rolled a "6 + 3", 6 is bigger than 5 and three is greater than two, and you bear off your two checkers!
Suppose you have 2 checkers in "r4" and 1 checker in "r1", you have rolled a "four + three", you bear off a single checker from "r4" with your dice quantity four, and for dice amount three you should move one checker from "r4" to "r1".
You have 3 checkers in "r6" and two checkers in "r3", 4 checkers in "r2" and three checkers in "r1". You have rolled a "5 + 4". Regrettably you will move 2 checkers from "r6" to "r2" and "r1", and you can not bear any checker off.
You have 3 checkers in "r6", three in "r5", 2 in "r4", four in "r2" and 3 in "r1", and you have rolled a "double3", since your "r3" is empty you should move 2 checkers from "r6" to "r3" and bear 2 checkers off from "r3".
You have 3 checkers in "r3", four checkers in "r2" and 5 checkers in "r1", you have rolled a "5 + 4". You will bear two checkers off from "r3".
You have 2 checkers in "r6", 4 checkers in "r5", 1 checker in "r4", three checkers in "r3", 3 checkers in "r2" and two checkers in "r1". You have rolled a "double4". You will bear one checker off from "r4", move 2 checkers from "r6" to "r2" and 1 checker from "r5" to "r1". Only a single checker has been born off.
Perhaps the worst position is when you have only two checkers remaining in "r2" and you roll one "1", for example a "three + 1". While three is larger than "r2", 1 is smaller sized, and you will bear one checker off but move the last one to "r1" and wait for the next hand. Exact same for "two + 1" or "four + 1" | | | |
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